Equivalent of IsValidClass Node in C++?

Development Programming & Scripting C++
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1

I am looking for a function equivalent to node (IsValidClass) in C++.

1

I tried something like this but the function doesn’t exist, or I don’t have the necessary include.

IsValidClass();

I can’t find the solution on Google either.

Do you know how to do it?
Thank you so much!!

2

ok… i found this in the Lyra code

TSubclassOf PartClass = ULyraDevelopmentStatics::FindClassByShortName(AssetName);

if (PartClass != nullptr)

I hope it works

3

Perhaps this is what you’re looking for?

UKismetSystemLibrary::IsValidClass(const UClass *Class);

The above method forwards to:

::IsValid(const UObject*);

4

Also you can do it like that :

if (IsValid(YourClass))
{
}

or

if (YourClass)
{
}
5

Thank you very much for your reply

1

However it appears to be a private member of the class

6

Just use IsValid().

7

Thanks for your reply
I’m going to try it.

Not sure if it will work though… seems to only work with classes derived from UObject.

1

This class is not derived class derived from UObject
2

But this is a derived class derived from UObject

3

3

4

5

So maybe I should use it this way

6

I’m going to try it and then come back here to say what happened.

Thank you very much for your help!!

8

UClass does derive from UObject. TSubclassOf is just a wrapper that holds a pointer to a UClass.

So IsValid() is correct.

And you shouldn’t need to call .Get() on a TSubclassOf. It should just work. I have tried it and it compiles.

edit: The reason it works with TSubclassOf despite not deriving from UObject is because it has an operator that will return the contained pointer and since that pointer does derive from a UObject, it should just work. These are implicit conversions that the compiler will do.

9

Ok, I will do as you say, thank you very much for your explanation!

10

Thank you so much :heart: