I know what it would mean before it, but what does it mean after?
It’s a Pointer to a Variable of type UTexture.
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Sounds good to me – thanks! The funny thing is, I searched high and low on Google for the answer, but nothing about it. It must be such an easy concept no one even talks about it, lol.
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The concept of pointers is well discussed 
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Consider lines:
UTexture* MyTexture; // defines a pointer to an object of type UTexture
MyTexture = NewObject<UTexture>();// instantiates the object (allocates memory and calls the constructor)
defines a variable called MyTexture that is a pointer to an object of type UTexture. A pointer is a variable that holds the ADDRESS of the object you are pointing to in memory. No memory is allocated for the object itself on the first line above.
See standard C or C++ docs for more details on pointers.
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That’s the weirdest thing for me – I get that it’s a pointer, but why does it come after the variable in Unreal C++, but seemingly always before in regular C++ examples online?
You can write
void* MyPointer;
or void * MyPointer;
or void *MyPointer;
Thats all fine, but if you write it directly after the type name its more clear that you define a pointer to that type.
But take care, if you create a list its better to put the star before the variable name, as
int* pt1, pt2, pt3;
…creates one pointer and two normal variables.
So you’d write
int *pt1, *pt2, *pt3;
Those might help explain it.
Make sure you don’t confuse it with a dereferencing operator also, which looks like *VariableName.
It doesn’t come after the variable, it comes after the type.
struct Type { // define a type
int foo;
};
Type * variable = NULL; // define a variable as pointer-to-type
variable = new Type(); // assign a value to a variable
(*variable).foo = 2; // dereference a pointer variable (style 1)
assert(variable->foo == 2); // dereference a pointer variable (style 2)
Style 1 and style 2 are equivalent unless very peculiar operator overloading is involved.
As jwatte said, it comes after the type, not the variable(name/label).
One of the major reason for this is C++ likes to reuse the hell out of operators, with * tacking triple duty… declaration of a pointer, dereference a pointer and multiplication, so this totally valid (and ugly) C++ code for example:
int *i, *j, k = 42;
i = j = &k;
std::cout << *i * *j << std::endl;
As jwatte said, it comes after the type, not the variable. The astericks operator pulls triple duty in C++, declaring a pointer, dereferencing a pointer and multiplication operation. Making the following horrid code valid:
int *i, *j, k = 42;
i = j = &k;
std::cout << *i * *j << std::endl;