What AND or NAND like booleans or others can do with ONE BRANCH what here takes TWO BRANCHES?

[usa423]

Thanks

[Ram07 (Ram)]

i think we can do like this - npc screen box bool variable and npc counter == 0 bool (drag from this NOT boolean), now you can do AND boolean for both of this and it should work fine without 2 branches

[usa423]

I didn’t quite understand. So run both of those to a NOT and then to AND? Can you clarify? thanks

[usa423]

This here did not work.

[Ram07 (Ram)]

for npc in screen box variable - NOT BOOLEAN … is not needed

[Nawrot]

Some references about BOOLEAN algebra:

Logic/logic gates:
https://www.electronics-tutorials.ws/boolean/bool_7.html

Next step Truth tables (like what to do if i have multiple inputs and outputs):

Truth table

And calulator that generates function/formula out ot inputs and outputs:

https://tma.main.jp/logic/index_en.html

[AlienRenders]

You don’t have a state for the false execution pin on the second branch node. So there’s no possible way to do what you’re asking.

You effectively have 3 execution states (TRUE, FALSE and NO EXECUTION). You need two branch nodes for that.

[usa423]

Ok, thank you for the links.

[usa423]

Thanks everyone that replied, I guess I will mark your post @AlienRenders as the solution (but everyone else also gets an A for effort). I didn’t know just thought there might be something that could be used in combo to do with one branch what the two was doing. Ok, thanks for clarifying that.

[AlienRenders]

If the last branch node had both pins connected to a return pin, then yeah, you could do something. You could return a boolean instead and you could get rid of both branch nodes.