TArray Find No operator found or suitable conversion

Development Programming & Scripting C++
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6

Hi guys,

the same error occurs for me even though I have overwitten the == operator.

To visualise what I’ve done so far here are some code snippets:

I’ve defined the struct within its own .H file:

USTRUCT()
struct FInventoryItem
{
	GENERATED_USTRUCT_BODY()
	UPROPERTY()
	AActor* aItemActor;
	UPROPERTY()
	FText ftDescription;

	FInventoryItem()
	{
		aItemActor = NULL;
		ftDescription = NSLOCTEXT("test_english", "PickupText", "PickupText");
	}

	bool operator == (const FInventoryItem rhs)
	{
		if (aItemActor == rhs.aItemActor && ftDescription.EqualTo(rhs.ftDescription))
		{
			return true;
		}
		else return false;
	}
};

Within a saperate class header I’ve defined an array which contains these Items:

TArray<FInventoryItem> arrInventory;

As soon as I call (within my .CPP):

arrInventory.Contains(AnotherFInventoryItem);

I get the compiler error :

binary '==' : no operator found which takes a left-hand operand of type 'const FInventoryItem' (or there is no acceptable conversion)

as well as:

could be 'bool FInventoryItem::operator ==(const FInventoryItem)' 
or 'bool operator ==(const FDialogueContextMapping &,const FDialogueContextMapping &)' 
or 'bool operator ==(const FDialogueContext &,const FDialogueContext &)'
...

So the compiler knows about my overwritten method but doesn’t use it. Any idea what I am missing?