Obviously, we can round/floor/ceiling to the nearest integer but how can I round to, say, the nearest multiple of 45? This seems like it should be very easy, so I feel like I’m missing something simple.

Thanks

Obviously, we can round/floor/ceiling to the nearest integer but how can I round to, say, the nearest multiple of 45? This seems like it should be very easy, so I feel like I’m missing something simple.

Thanks

I have no idea if there is a node for that, but this here should do what you want:

I just converted this code to BP:

```
int roundUp(int numToRound, int multiple)
{
if (multiple == 0)
return numToRound;
int remainder = abs(numToRound) % multiple;
if (remainder == 0)
return numToRound;
if (numToRound < 0)
return -(abs(numToRound) - remainder);
return numToRound + multiple - remainder;
}
```

Yep, it sure does. Thanks, eXi.

Forgive me if I’m wrong, but I believe it could be done with just three nodes (seen below).

I may be missing something however.

Much more elegant.

Div and round nodes

Even more elegant!

Based on the code I found on next link, you can round up or down to the closest multiple:

Code link: Round the given number to nearest multiple of 10 - GeeksforGeeks

`# Python3 code to round the given`

`# integer to a whole number`

`# which ends with zero.`

`# function to round the number`

`def`

`round`

`( n ):`

` `

`# Smaller multiple`

` `

`a `

`=`

`(n `

`/`

`/`

`10`

`) `

`*`

`10`

` `

` `

`# Larger multiple`

` `

`b `

`=`

`a `

`+`

`10`

` `

` `

`# Return of closest of two`

` `

`return`

`(b `

`if`

`n `

`-`

`a > b `

`-`

`n `

`else`

`a)`

`# driver code`

`n `

`=`

`4722`

`print`

`(`

`round`

`(n))`

`# This code is contributed by "Sharad_Bhardwaj".`

This is all you need to do (*n* is the number and *m* is the multiple); works with decimals, too: