Obviously, we can round/floor/ceiling to the nearest integer but how can I round to, say, the nearest multiple of 45? This seems like it should be very easy, so I feel like I’m missing something simple.
Thanks
I have no idea if there is a node for that, but this here should do what you want:
I just converted this code to BP:
int roundUp(int numToRound, int multiple)
{
if (multiple == 0)
return numToRound;
int remainder = abs(numToRound) % multiple;
if (remainder == 0)
return numToRound;
if (numToRound < 0)
return -(abs(numToRound) - remainder);
return numToRound + multiple - remainder;
}
2 Likes
Yep, it sure does. Thanks, eXi.
Forgive me if I’m wrong, but I believe it could be done with just three nodes (seen below).
I may be missing something however.
Much more elegant.
Div and round nodes
Even more elegant!
Based on the code I found on next link, you can round up or down to the closest multiple:
Code link: Round the given number to nearest multiple of 10 - GeeksforGeeks
# Python3 code to round the given
# integer to a whole number
# which ends with zero.
# function to round the number
def round ( n ):
# Smaller multiple
a = (n / / 10 ) * 10
# Larger multiple
b = a + 10
# Return of closest of two
return (b if n - a > b - n else a)
# driver code
n = 4722
print ( round (n))
# This code is contributed by "Sharad_Bhardwaj".
This is all you need to do (n is the number and m is the multiple); works with decimals, too:
2 Likes
Maybe i am missing something, but would thos whole rounding to a constant not just be like snapping to grid? Whatever you would feed into a snap to grid node, would become your constant, and every value gets snapped to the closest multiple of that.
6 Likes
Perfect for what I needed to do!
This was the easiest/best solution for me, thank you!