I know this is an old question but I was also looking for an answer. I found that you can use the c++11 normal_distribution function. The following function will return a number with a mean of 5.0 and a deviation of 0.5. You need to #include <random>.
float AActor::NormalDistribution()
{
std::random_device rd{};
std::mt19937 gen{ rd() };
std::normal_distribution<float> d{ 5.0f, 0.5f };
return d(gen);
}