Hi There,
Is there a way to calculate the distance between two xyz coordinates manually.
I just need to double check the values I get in game are correct
Would really appreciate a straightforward way to do this for someone extraordinarily bad at maths!
Hi Delta,
something like this:
sqrt( sqr(v2.x-v1.x) + sqr(v2.y-v1.y) + sqr(v2.z-v1.z) )
Squaring the delta’s removes any signs.
subtract the position of one thing from the other, this gets you the difference between the two, the vector
because we only care about the absolute value of the vector, use the…absolute value (lol) to drop the sign (we don’t know what order you did the first step, (a - b) or (b - a) wont matter if we use absolut-value
get the length of that vector
there should be nodes in BPs or commands on C++ to do this. I know there is also a Distance node or VectorLength in Materials if you are doing your maths there…
Hi RD, huge thanks, but if its not too much trouble,could you please give me a worked example?
Any chance of a worked example please?
Nice, however if I wanted to do the calculation on paper could you walk me through how to do it given 2 X,Y,Z coordinates
Ok, it’s just really pythagoras’ theorum but in 3D (Hypotenuse squared = Adjacent squared + opposite squared)
so say you have two vectors 1=(0,0,0) 2=(100,100,100), you would calculate it by:
x part = (0-100) * (0-100) = -100 * -100 = 10000
y part = (0-100) * (0-100) = -100 * -100 = 10000
z part = (0-100) * (0-100) = -100 * -100 = 10000
so then
distance squared = 10,000 + 10,000 + 10,000
or
distance = square root of (30,000)
distance = 173.2
Huge thanks!
