How I Get All Functions of one Object???

Development Programming & Scripting C++
1

Hi, I Create a Plugin,
I would like to know how I can do to create a list of all available functions in an object in C++

2 


void UMyClass::ListAllObjectUFunctions(const UObject* Object) {

    for ( TFieldIterator<UFunction> FIT ( Object->GetClass(), EFieldIteratorFlags::IncludeSuper ); FIT; ++FIT) {

        UFunction* Function = *FIT;
        UE_LOG ( LogTemp, Log, TEXT( "Function Found:  %s();" ), *Function->GetName() );

    }
}
3

Thanks…
I spent a lot of time trying to figure out this logic …
Is there any way to find out what parameters are required to perform this function?

5

Function parameters (and return values) are instantiated as UProperty’s as well, it is possible to iterate over them like so (random example from source code):


for ( TFieldIterator<UProperty> It(Function); It && (It->PropertyFlags&(CPF_Parm|CPF_ReturnParm)) == CPF_Parm; ++It )
    {
        LastParameter = *It;
    }

You can look through the source to find some usage examples on how to process the parameters.

6

Use “FProperty” instead of “UProperty”

for ( TFieldIterator<FProperty> It(Function); It && (It->PropertyFlags&(CPF_Parm|CPF_ReturnParm)) == CPF_Parm; ++It )
    {
        LastParameter = *It;
    }

This worked for me