How can I expose a pointer for custom type?

Development Programming & Scripting
1

Hi,

i’ve got few structs inherited from one.

USTRUCT()
struct FBaseStruct { GENERATED_USTRUCT_BODY() }
USTRUCT
struct FChildStruct : public FBaseStruct { GENERATED_USTRUCT_BODY() }

Something like this. Then in other class i have TArray which consist of FBaseStruct and FChildStruct objects. Everything works as intended, But i want to be able to edit struct properties within editor details panel.

Changing

TArray<FBaseStruct*>

to

UPROPERTY(..)
TArray<FBaseStruct>

exposes structs to editor but every object is then FBaseStruct, no matter what i insert, as it should be.

So is there a way to expose pointer to custom type or some other solution for this?

Thanks in advance.

Edit: i get the following error once i declare array of pointers as UPROPERTY is below

     Inappropriate '*' on variable of type 'FBaseStruct', cannot have an exposed pointer to this type.
2

I guess you searching for BlueprintType specifier?

3

Nope, this does nothing.