I agree, the force of aerodynamic resistance will play a tangible role only at high speeds. Suppose our super car moving with speed = 360 km / h = 100 m / s. Lets calculate Drad Force. DragForce = 2m^2 * 0.3 * 1.2kg/m^3 * (100m/s * 100m/s)*0.5 = 3600 Nutons. Let’s assume that at the maximum speed the engine of our super car develops a torque equal to 500Nm, 6 gear is equal to 0.7, the diff gear = 4. We find the wheel torque. WheelTorque= Engine torque * Gear * DiffGear. WheelTorque=500Nm * 0.7 * 4 = 1400 Nm. Now divide this value into the radius of the wheel to find out the frictional force that the wheels place on the road - this will be the traction force. Traction Force = WheelTorque \ WheeelRadius. Traction Force = 1400Nm / 0.34m = 4117N. We see that even with such a huge torque of the engine (500 !!!) at very high revs(~7000-8000 rpm), which is hardly possible with conventional engines, the force of the aerodynamic drag approaches the traction force. Simply put, at such a high speed(>360 km/h), the air resistance force completely compensates for the traction force, and the car will not be able to accelerate even more. There will already have to adjust the aerodynamic parameters of the car - to reduce the coefficient of aerodynamic resistance, and the cross-sectional area of the car.