How do we check if a Widget is currently on the screen before we “Remove from Parent?”
If true, remove.
If false, do nothing.
Thanks!
How do we check if a Widget is currently on the screen before we “Remove from Parent?”
If true, remove.
If false, do nothing.
Thanks!
Use the IsVisible node from the Widget blueprint.
In 4.11 version of the engine I use IsInViewport
function. I’m not sure if it’s new or already was present in previous versions.
Hello.
What about 4.21.1? Cant find any of those
I guarantee that both of those functions exist in 4.22 & 4.23
To verify this for yourself you can right click in any empty section of event graph, uncheck “context sensitive” and type in “is visible” and “is in viewport”.
If you are dragging off a node, right clicking, and typing in “is visible” or “is in viewport” then you are not dragging off a valid target, make sure you are targeting a widget.
Currently using UE 5.3 and I would like to know if there is any concenseous on which to use?
(is visible VS is in viewport)
How to do this “Tutorial Screen Widget” Reference node ???
That is a variable. Once you have a variable of type {Your Widget} in the blueprint you can just drag it into the scene or right click and select “Get {Your Widget’s variable name}”. In this instance his variable is called “Tutorial Screen Widget”