it looks complicated but since its almost repetitive its not that hard u just need to concentrate on all options and they are not many, is the number 1 or 2 or … 9 digit and after decimal is almost same, there i remove a coma if the number is greater than 1000, also there is something u cant do in normal random number node - u can choose the digits of the after decimal point so 1 to 3 means .1 or .2 or .3 and random float will give you all 6 digits range from .1 to .3 and thats horrible long story if u dont need all, u can just floor them probably and if the number is .4 repeat the process, so all .1 .2 and .3 will have equal chance.
I can share this BP if you can post it somewhere in useful place, the random number is stored in arrays each digit in specific index and all comas are cleared from the number
I made this because I had a win chance big flash appearance and if it was bigger than 1000 it looked like “congratulations it took you 1,583 attempts” where you smashed your keyboard 1583 times and it looks like you did it 1 times point 583 very underestimating if thats the word