In this case you can just find nearest actor
But update the array based on what resources you have.
That way when fishing hut 1 runs out it gets removed from the array.
Also less expensive than the class option.
In this case you can just find nearest actor
But update the array based on what resources you have.
That way when fishing hut 1 runs out it gets removed from the array.
Also less expensive than the class option.