How to "expose on spawn" a constructor param in C++?

Development Programming & Scripting
14

OK guys this is getting ridiculous. At this point you’re not trying to get to an answer anymore. I’m turning off notifications. But before I do I will once again suggest the very easy (but not elegant way) to do what you want. Here is a sample class that does it. It will work fine as long as you are using the main thread – and since that’s the only place you can spawn from, this will always work as long as that doesn’t change.

H:

UCLASS()
class SHOOTER_API AMyActor : public AActor
{
	GENERATED_BODY()

public:
	AMyActor(const FObjectInitializer& ObjectInitializer);

	UPROPERTY(EditAnywhere, BlueprintReadWrite)
	int MyVar1;

	UPROPERTY(EditAnywhere, BlueprintReadWrite)
	bool MyVar2;

	static AMyActor* Spawn(UWorld* world, int myVar1, bool myVar2);

private:
	static bool ParamsSet;
	static int Param_Var1;
	static bool Param_Var2;
};

CPP:

int AMyActor::Param_Var1 = -1;
bool AMyActor::Param_Var2 = false;
bool AMyActor::ParamsSet = false;

AMyActor::AMyActor(const FObjectInitializer& ObjectInitializer)
	:	AActor(ObjectInitializer)
{
	if(!ParamsSet)
	{
		UE_LOG(LogTemp, Error, TEXT("AMyActor spawned without using internal Spawn function!"));
	}
	else
	{
		MyVar1 = AMyActor::Param_Var1;
		MyVar2 = AMyActor::Param_Var2;
	}
}

AMyActor* AMyActor::Spawn(UWorld* world, int myVar1, bool myVar2)
{
	AMyActor::Param_Var1 = myVar1;
	AMyActor::Param_Var2 = myVar2;
	AMyActor::ParamsSet = true;

	AMyActor* myActor = world->SpawnActor<AMyActor>(); 	// fill Spawn() with parameters as you need

	AMyActor::ParamsSet = false;

	return myActor;
}